(2x^7y^-1/8x^-4y^3)^-2

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Solution for (2x^7y^-1/8x^-4y^3)^-2 equation:


D( x )

x = 0

x^-4*((2*x^7*y^-1)/8)*y^3 = 0

x = 0

x = 0

x^-4*((2*x^7*y^-1)/8)*y^3 = 0

x^-4*((2*x^7*y^-1)/8)*y^3 = 0

1/4*x^3*y^2 = 0 // : 1/4*y^2

x^3 = 0

x = 0

x in (-oo:0) U (0:+oo)

(x^-4*((2*x^7*y^-1)/8)*y^3)^-2 = 0

16*x^-6*y^-4 = 0 // : 16*y^-4

x^-6 = 0

x naleu017Cy do O

x belongs to the empty set

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